Extending the namespace std
From cppreference.com
[edit] Adding declarations to std
It is undefined behavior to add declarations or definitions to namespace std
or to any namespace nested within std
, with a few exceptions noted below
#include <utility> namespace std { // a function definition added to namespace std: undefined behavior pair<int, int> operator+(pair<int, int> a, pair<int, int> b) { return {a.first+b.first, a.second+b.second}; } }
It is allowed to add template specializations for any standard library template to the namespace std
only if the declaration depends on a user-defined type and the specialization satisfies all requirements for the original template, except where such specializations are prohibited.
This section is incomplete Reason: mini-example |
- It is undefined behavior to declare a full specialization of any member function of a standard library class template
This section is incomplete Reason: mini-example |
- It is undefined behavior to declare a full specialization of any member function template of a standard library class or class template
This section is incomplete Reason: mini-example |
- It is undefined behavior to declare an full or partial specialization of any member class template of a standard library class or class template.
This section is incomplete Reason: mini-example |
- None of the type traits defined in <type_traits> may be specialized for a user-defined type, except for std::common_type.
- Specializing the template std::complex for any type other than float, double, and long double is unspecified.
- Specializations of std::atomic must have a deleted copy constructor, a deleted copy assignment operator, and a constexpr value constructor.
- Specializations of std::shared_ptr and std::weak_ptr must be
CopyConstructible
andCopyAssignable
. In addition, specializations of std::shared_ptr must beLessThanComparable
, and convertible to bool.
- Specializations of std::istreambuf_iterator must have a trivial copy constructor, a constexpr default constructor, and a trivial destructor.
- std::unary_function and std::binary_function may not be specialized.
It is allowed to explicitly instantiate a template defined in the standard library only if the declaration depends on the name of a user-defined type and the instantiation meets the standard library requirements for the original template.
This section is incomplete Reason: mini-example |
[edit] Other restrictions
The namespace std
may not be declared as an inline
namespace.