std::result_of

Defined in header `<type_traits>`
template< class > class result_of; //not defined	(1)	(since C++11)
template< class F, class... ArgTypes > class result_of<F(ArgTypes...)>;	(2)	(since C++11)

Deduces the return type of a function call expression at compile time.

`F` must be a callable type, reference to function, or reference to callable type. Invoking `F` with `ArgTypes...` must be a well-formed expression	(since C++11)
`F` and all types in `ArgTypes` can be any complete type, array of unknown bound, or (cv-qualified) void	(since C++14)

template <class> struct result_of;
 
namespace detail {
template <class F, class... Args>
inline auto INVOKE(F&& f, Args&&... args) ->
    decltype(forward<F>(f)(forward<Args>(args)...)) {
      return forward<F>(f)(forward<Args>(args)...);
}
 
template <class Base, class T, class Derived>
inline auto INVOKE(T Base::*&& pmd, Derived&& ref) ->
    decltype(forward<Derived>(ref).*forward<T Base::*>(pmd)) {
      return forward<Derived>(ref).*forward<T Base::*>(pmd);
}
 
template <class PMD, class Pointer>
inline auto INVOKE(PMD&& pmd, Pointer&& ptr) ->
    decltype((*forward<Pointer>(ptr)).*forward<PMD>(pmd)) {
      return (*forward<Pointer>(ptr)).*forward<PMD>(pmd);
}
 
template <class Base, class T, class Derived, class... Args>
inline auto INVOKE(T Base::*&& pmf, Derived&& ref, Args&&... args) ->
    decltype((forward<Derived>(ref).*forward<T Base::*>(pmf))(forward<Args>(args)...)) {
      return (forward<Derived>(ref).*forward<T Base::*>(pmf))(forward<Args>(args)...);
}
 
template <class PMF, class Pointer, class... Args>
inline auto INVOKE(PMF&& pmf, Pointer&& ptr, Args&&... args) ->
    decltype(((*forward<Pointer>(ptr)).*forward<PMF>(pmf))(forward<Args>(args)...)) {
      return ((*forward<Pointer>(ptr)).*forward<PMF>(pmf))(forward<Args>(args)...);
}
} // namespace detail
 
// C++11 implementation:
template <class F, class... ArgTypes>
struct result_of<F(ArgTypes...)> {
    using type = decltype(detail::INVOKE(
        declval<F>(), declval<ArgTypes>()...
    ));
};
 
// C++14 implementation:
namespace detail {
template <class F, class... ArgTypes>
struct invokeable {
    template <typename U = F>
    static auto test(int) -> decltype(INVOKE(
        declval<U>(), declval<ArgTypes>()...
    ), void(), true_type());
 
    static auto test(...) -> false_type;
 
    static constexpr bool value = decltype(test(0))::value;
};
 
template <bool B, class F, class... ArgTypes>
struct _result_of {
    using type = decltype(INVOKE(
        declval<F>(), declval<ArgTypes>()...
    ));
};
 
template <class F, class... ArgTypes>
struct _result_of<false, F, ArgTypes...> { };
} // namespace detail
 
template <class F, class... ArgTypes>
struct result_of<F(ArgTypes...)> :
    detail::_result_of<detail::invokeable<F, ArgTypes...>::value, F, ArgTypes...> { };

[edit] Notes

As formulated in C++11, std::result_of would fail to compile when F(ArgTypes...) is ill-formed (e.g. when F is not a callable type at all). C++14 changes that to a SFINAE (when F is not callable, std::result_of<F(Args...)> simply doesn't have the type member).

[edit] Examples

std::result_of can be used to determine the result of invoking a functor, in particular if the result type is different for different sets of arguments:

Run this code

#include <type_traits>
 
struct S {
    double operator()(char, int&);
    float operator()(int);
};
 
struct C {
    double Func(char, int&);
};
 
int main()
{
    // the result of invoking S with char and int& arguments is double
    std::result_of<S(char, int&)>::type f = 3.14; // f has type double
    static_assert(std::is_same<decltype(f), double>::value, "");
 
    // the result of invoking S with int argument is float
    std::result_of<S(int)>::type d = 3.14; // f has type float
    static_assert(std::is_same<decltype(d), float>::value, "");
 
    // result_of can be used with a pointer to member function as follows
    std::result_of<decltype(&C::Func)(C, char, int&)>::type g = 3.14;
    static_assert(std::is_same<decltype(g), double>::value, "");
}

This program takes advantage of the C++14 changes to overload two functions on the "callability" of a template parameter:

Run this code

#include <type_traits>
#include <iostream>
 
template<class T>
typename std::result_of<T(int)>::type
f(T& t)
{
    std::cout << "overload of f for callable T\n";
    return t(0);
}
 
template<class T, class U>
int f(U u)
{
    std::cout << "overload of f for non-callable T\n";
    return u;
}
 
struct S {};
 
int main() {
  f<S>(1); // fails to compile in C++11, calls the non-callable overload in C++14
}

Output:

overload of f for non-callable T

[edit] See also

declval

(C++11)

obtains the type of expression in unevaluated context
(function template)

Language
Standard library headers
Concepts
Utilities library
Strings library
Containers library
Algorithms library
Iterators library
Numerics library
Input/output library
Localizations library
Regular expressions library (C++11)
Atomic operations library (C++11)
Thread support library (C++11)

Type support (basic types, RTTI, type traits)
Dynamic memory management
Error handling
Program utilities
Variadic functions
Date and time
Function objects
initializer_list (C++11)
bitset
hash (C++11)
Relational operators
rel_ops::operator!=rel_ops::operator>rel_ops::operator<=rel_ops::operator>=
Pairs and tuples
pair
tuple (C++11)
piecewise_construct_t (C++11)
piecewise_construct (C++11)
Swap, forward and move
swap
forward (C++11)
move (C++11)
move_if_noexcept (C++11)
declval (C++11)

Member type	Definition
`type`	the return type of the `Callable` type `F` if invoked with the arguments `ArgTypes...`. Only defined if F can be called with the arguments ArgTypes... in unevaluated context. (since C++14)

std::result_of

Contents

[edit] Member types

[edit] Helper types

[edit] Possible implementation

[edit] Notes

[edit] Examples

[edit] See also

template< class T > using result_of_t = typename result_of<T>::type;		(since C++14)