std::is_assignable, std::is_trivially_assignable, std::is_nothrow_assignable
From cppreference.com
Defined in header
<type_traits>
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template< class T, class U >
struct is_assignable; |
(1) | (since C++11) |
template< class T, class U >
struct is_trivially_assignable; |
(2) | (since C++11) |
template< class T, class U >
struct is_nothrow_assignable; |
(3) | (since C++11) |
1) If the expression std::declval<T>() = std::declval<U>() is well-formed in unevaluated context, provides the member constant
value
equal true. For any other type, value
is false.
2) same as (1), but evaluation of the assignment expression will not call any operation that is not trivial.
3) same as (1), but the evaluation of the assignment expression will not call any operation that is not noexcept.
Contents |
Inherited from std::integral_constant
Member constants
value
[static]
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true if T is assignable from U , false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
Member types
Type | Definition |
value_type
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bool
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type
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std::integral_constant<bool, value> |
[edit] Example
Run this code
#include <iostream> #include <string> #include <type_traits> struct Ex1 { int n; }; int main() { std::cout << std::boolalpha << "int is assignable from int? " << std::is_assignable<int, int>::value << '\n' // 1 = 1; wouldn't compile << "int& is assignable from int? " << std::is_assignable<int&, int>::value << '\n' // int a; a = 1; works << "int is assignable from double? " << std::is_assignable<int, double>::value << '\n' << "int& is nothrow assignable from double? " << std::is_nothrow_assignable<int&, double>::value << '\n' << "string is assignable from double? " << std::is_assignable<std::string, double>::value << '\n' << "Ex1& is trivially assignable from const Ex1&? " << std::is_trivially_assignable<Ex1&, const Ex1&>::value << '\n'; }
Output:
int is assignable from int? false int& is assignable from int? true int is assignable from double? false int& is nothrow assignable from double? true string is assignable from double? true Ex1& is trivially assignable from const Ex1&? true
[edit] See also
(C++11)(C++11)(C++11)
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checks if a type has a copy assignment operator (class template) |
(C++11)(C++11)(C++11)
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checks if a type has a move assignment operator (class template) |