malloc
Defined in header
<stdlib.h>
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void* malloc( size_t size );
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Allocates size
bytes of uninitialized storage.
If allocation succeeds, returns a pointer to the lowest (first) byte in the allocated memory block that is suitably aligned for any object type.
If size
is zero, the behavior is implementation defined (null pointer may be returned, or some non-null pointer may be returned that may not be used to access storage).
A previous call to free or realloc that deallocates a region of memory synchronizes-with a call to malloc that allocates the same or a part of the same region of memory. This synchronization occurs after any access to the memory by the deallocating function and before any access to the memory by |
(since C11) |
Contents |
[edit] Parameters
size | - | number of bytes to allocate |
[edit] Return value
Pointer to the beginning of newly allocated memory or null pointer if error has occurred. The pointer must be deallocated with free().
[edit] Example
#include <stdio.h> #include <stdlib.h> int main(void) { /* Allocate an array of four integers. */ int *pa = malloc(4*sizeof(int)); if (pa == NULL) { printf("malloc() failed in file %s at line # %d", __FILE__,__LINE__); exit(1); } /* Initialize array A with values. */ for (int ndx=0; ndx < 4; ndx++) pa[ndx] = ndx; /* Print one of the array elements. */ printf("pa[3] = %d\n", pa[3]); /* Deallocate array pa. */ free(pa); return 0; }
Output:
pa[3] = 3
[edit] See also
C++ documentation for malloc
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